• plyth@feddit.org
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    7 days ago

    You are right, I considered that.

    The average per year is calculated from that number by roughly multiplying with 10 in Europe. I have looked that up and not multiplied by hours in a year.

        • lime!@feddit.nu
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          7 days ago

          right, so that’s most likely optimal placement, with peak efficiency being reached for a little while each day as long as the weather is good. if they lie flat, you can lose as much as 90% of that energy, and that’s still with proper maintenance. flat panels also don’t self-clean, so maintenance would be even higher.

          basically, you can probably skip the multiplication altogether.

          • plyth@feddit.org
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            7 days ago

            It’s not the most optimal. It’s for a 20% panel slightly south of England:

            However, in Michigan, which receives only 1400 kWh/m2/year,[3] annual energy yield drops to 280 kWh for the same panel. At more northerly European latitudes, yields are significantly lower: 175 kWh annual energy yield in southern England under the same conditions

            https://en.m.wikipedia.org/wiki/Solar-cell_efficiency

              • plyth@feddit.org
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                6 days ago

                I have calculated conservatively. The result is the lower bound. With optimal conditions twice the energy could be generated.

                • lime!@feddit.nu
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                  6 days ago

                  it’s not though, because we’ve already shown that it was overstated by a factor of 10.

                  • plyth@feddit.org
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                    6 days ago

                    No, you thought that I had inflated numbers and thus reduced the factor but that reduction is not necessary. There is even another underestimation because the land for the tracks is wider than three meters.