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  • 16 Comments
Joined 5 years ago
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Cake day: December 23rd, 2020

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  • Illegal content is already illegal.

    I think it actually is more complicated. There are anti obscenity laws in the United States where these companies (Steam and Itch.io, but also Visa, Mastercard, Stripe and Paypal) are based. The way those laws have been applied have been mostly permissive in the recent past, but I think there’s reason to believe that this could change quickly. We may find ourselves in a situation where the highest court decides that this has all been illegal this whole time. Procedural and legal norms are feeling a bit shaky these days. People wonder why payment processors would bend over backwards on behalf of some group of aussie weirdos, but maybe being on their good side isn’t the concern. Maybe it’s that they’re trying to self regulate to get ahead of any government action. Collective Shout may just be highlighting to them the most risky instances, making it so that they have no plausible deniability with regards to the content they are processing payments for.



  • Bilb!@lemmy.mltoScience Memes@mander.xyzUS education
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    3 days ago

    It’s worth remembering that this is not the type of textbook used in American public schools and most American students do not attend weird private religious schools. I was also raised as a Catholic and learning about science (including evolution through natural selection, of course) was always encouraged. Evangelicals are nuts.








  • Bilb!@lemmy.mltoMicroblog Memes@lemmy.worldWelp
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    19 days ago

    I’ve actually wanted such a system to exist and to be available for general use so that one could made social communities for, e.g. (real) people over the 30. Make it work similar to oauth. I think that sounds great honestly. Of course, if you wanted to be strict about it your community would only be from places that have this verification system in place.




  • Bilb!@lemmy.mltoScience Memes@mander.xyzCursed
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    29 days ago

    You could arrange them that way, but the goal is to find the way to pack the small squares in a way that results in the smallest possible outer square. In the solution shown, the length of one side of the outer square is just a bit smaller than 12. If you pack them normally, the length would be larger than exactly 12. (1 = the length of one side of the smaller squares.)